Question

find the perimeter of rectangle whose length is 7 3/10 and breadth is 3/5 cm is ?​

Answer 1

$\tt{{Given:-}}$

Length of rectangle = $7\tt\dfrac{3}{10}$ cm

Breadth of rectangle = $\tt\dfrac{3}{5}$ cm

$\tt{{To}}$$\tt{{Find:-}}$

• Perimeter of rectangle

$\tt{{Solution:-}}$

Length of rectangle = $7\tt\dfrac{3}{10}$ cm

Let us change mixed fraction into improper fraction :

= $\tt\dfrac{73}{10}$ cm

We will apply the Formula,

Perimeter = 2 (length + breadth)

= 2 ( $\tt\dfrac{73}{10} +\tt\dfrac{3}{5}$)

= 2 ( $\tt\dfrac{73+3\times 2}{10}$ )

= 2 ( $\tt\dfrac{73+6}{10}$ )

= 2 ( $\tt\dfrac{79}{10}$ )

= $\tt\dfrac{79}{5}$

= $15\tt\dfrac{4}{5}$ cm

$\therefore \tt{{Perimeter=}}$$15\tt\dfrac{4}{5}$ cm or $\tt{{15.8}}$ cm

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Formulas for Rectangle:

• Area = Length × Breadth

• Perimeter = 2 (length + breadth)

• Length of diagonal (d) = √√(l² + b²)

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Answer 2

Answer:

Given :-

• A rectangle whose length is $7\tt\dfrac{3}{10}$ cm and breadth is $\dfrac{3}{5}$ cm.

To Find :-

• What is the perimeter of the rectangle.

Formula Used :-

$\boxed{\bold{\large{Perimeter\: =\: 2(l\: +\: b)}}}$

Solution :-

Given :

• Length of the rectangle = $7\tt\dfrac{3}{10}$ = $\dfrac{73}{10}$
• Breadth of the rectangle = $\dfrac{3}{5}$

According to the question by using the formula we get,

⇒ P = 2( $\dfrac{73}{10}$ + $\dfrac{3}{5}$ )

⇒ P = 2( $\dfrac{73 + 6}{10}$ )

⇒ P = 2( $\dfrac{79}{10}$ )

⇒ P = ( $\dfrac{79}{5}$ )

➠ P = 15.8 cm

$\therefore$ The perimeter of the rectangle is 15.8 cm .

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