Question

find the perimeter of rectangle
whose length is 7(3/10)cm
and breadth is 3/5cm

pls answer it's urgent I will mark you as brainlist​

Answer 1

Answer:

Here , l = 15 cm and b = 12 cm . <br> P = 2(15 + 12) = 54 cm . <br>

Perimeter of rectangle is 54 cm .

Answer 2

Given:-

• Length of Rectangle = $7\dfrac{3}{10}=\dfrac{73}{10}$

• Breadth of Rectangle = $\dfrac{3}{5}$

To Find:-

• It's Perimeter

Formula Used:-

• ${\boxed{\bf{Perimeter\:of\: Rectangle=2(l+b)}}}$

Solution:-

Using Formula,

$\sf :\implies\:Perimeter\:of\: Rectangle=2(l+b)$

Putting values,

$\sf :\implies\:Perimeter\:of\: Rectangle=2(\dfrac{73}{10}+\dfrac{3}{5})$

$\sf :\implies\:Perimeter\:of\: Rectangle=2\times \dfrac{73+6}{10}$

$\bf :\implies\:Perimeter\:of\: Rectangle=\dfrac{79}{5}\:cm^2$

or,

$\bf :\implies\:Perimeter\:of\: Rectangle=15.8\:cm^2$

Hence, The Perimeter of given Rectangle is 79/5 cm² or 15.8 cm².

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