Math, asked by 2001roars, 1 month ago

Find the perimeter of Rectangle whose length is 8 m and breadth is 5 m.

Answers

Answered by Anonymous
7

Correct Question-:

  • Find the perimeter of Rectangle whose length is 8 m and breadth is 5 m.

AnswEr-:

  • \underline{\boxed{\star{\sf{\blue{ Perimeter_{(Rectangle)}  \: =26 m }}}}}

Explanation-:

  •  \frak{Given \:\: -:} \begin{cases} \sf{The\:Length \:of\:Rectangle\:\:is\:= \frak{8m}} & \\\\ \sf{Breadth \:of\:Rectangle \:is \:=\:\frak{5m}}\end{cases} \\\\

Figure related to the question-:

  • \setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 8 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 5 m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

  •  \frak{To\:Find \:\: -:} \begin{cases} \sf{The\:Perimeter \:of\:Rectangle.}\end{cases} \\\\

\dag{\underline {\sf{Solution \:of\:Question \:-:\:}}}\\\\

\underbrace{\sf{\large{Understanding \:Concept \:-:}}}

  • We have to find the Perimeter of Rectangle.

As, we know that ,

  • \underline{\boxed{\star{\sf{\blue{ Perimeter_{(Rectangle)}  \: = \: 2 \times ( Length + Breadth)}}}}}

  •  \frak{Here \:\: -:} \begin{cases} \sf{The\:Length \:of\:Rectangle\:\:is\:= \frak{8m}} & \\\\ \sf{Breadth \:of\:Rectangle \:is \:=\:\frak{5m}}\end{cases} \\\\

Now , By putting known Values in Formula,

  • \longrightarrow {\sf{ 2 (8  + 5)}}

  • \longrightarrow {\sf{ 2 ( 13)}}

  • \longrightarrow {\sf{ 26 m}}

\dag{\underline {\sf{ Hence :-:\:}}}

  • \underline{\boxed{\star{\sf{\blue{ Perimeter_{(Rectangle)}  \: =26 m }}}}}

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Answered by ravikaraghar123
2

Length= 8m, Breadth =5m

Perimeter of rectangle = 2 (l+b)

Perimeter = 2(8+5)

= 2×13

= 26m

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