Question

find the perimeter of rectangle whose one side measure 20 m and the diagonal is 29 m.

Answer 1

let a let a rectangle ABCD,A

B=20m and AC diagonal=29m

now in ∆ ABC, by Pythagoras theorem

AC^2= AB^2+BC^2

(29)^2= (20)^2+BC^2

841=400+BC^2

441=BC^2

BC=21m

perimeter of rectangle ABCD=2(l+b)

=2(20+21)m

=2(41)m

perimeter of rectangle ABCD=82m

Answer 2

Answer:

Breadth = 20 m

Length = ?

Diagonal = 29 m

by Pythagoras property

(d)^2 =(B)^2 +( L)^2

29^2=20^2 + X^2

841 =400 + x^2

x^2 = 841- 400

x^2 = 441

x = root under 441

x = 21 m

so length = 21 m

perimeter = 2 (l+b)

= 2× 41

= 82 m ANSWER

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