find the perimeter of rectangle whose one side measure 20 m and the diagonal is 29 m.
Answers
Answered by
75
Let the length (AB) be xm.
Breadth (BC) = 20m. (Given)
Diagonal (AC) = 29m (given)
ATQ
(AC)^2 = (AB)^2 + (BC)^2
(29)^2 = (x)^2 + (20)^2
841 = x^2 + 400
841 - 400 = x^2
√441 = x
21 = x
Hence length of the rectangle be 21m.
Perimeter of rectangle = 2(l + b)
= 2(20 + 21)
= 2 *41
= 81m
Breadth (BC) = 20m. (Given)
Diagonal (AC) = 29m (given)
ATQ
(AC)^2 = (AB)^2 + (BC)^2
(29)^2 = (x)^2 + (20)^2
841 = x^2 + 400
841 - 400 = x^2
√441 = x
21 = x
Hence length of the rectangle be 21m.
Perimeter of rectangle = 2(l + b)
= 2(20 + 21)
= 2 *41
= 81m
rajveerrao:
tnqq for answere
Answered by
11
this two photos is answer
Attachments:
Similar questions