Math, asked by hv0310716, 3 months ago

Find the perimeter of rectangle whose whose whose length is 40 cm and diagonal is 41cm?

Answers

Answered by BrainMistress
3

Answer:

Perimeter= 98cm

Step-by-step explanation:

The perimeter of the rectangle= 2 (Length + Width)

                                                   =  2 ( 40 + 9)

                                                   =   2 x 49

                                                    =   98cm

Answered by INSIDI0US
59

Answer:

Question :-

Find the perimeter of rectangle whose whose whose length is 40 cm and diagonal is 41cm ?

Answer :-

  • The perimeter of the rectangle is 98cm.

Given :-

  • Length of the rectangle = 40cm.
  • Diagonal of the rectangle = 41cm.

To find :-

  • We have to find the perimeter of the rectangle.

Step-by-step explanation :-

  • As we see, that we are given the length and the diagonal of the rectangle.
  • But to find the perimeter of the rectangle, firstly we will have to find the breadth of the rectangle.
  • So, by using the required formula we will find out the breadth of the rectangle.

Required formula is as follows :-

 {\underline{\boxed{\sf {(Diagonal)^2\ =\ (Length)^2\ +\ (Breadth)^2}}}}

Here,

  • Diagonal = 41cm.
  • Length = 40cm.

By applying the values, we get :-

 \sf \mapsto {(Diagonal)^2\ =\ (Length)^2\ +\ (Breadth)^2}

 \sf \mapsto {(41cm)^2\ =\ (40cm)^2\ +\ (Breadth)^2}

 \sf \mapsto {1681cm^2\ =\ 1600cm^2\ +\ (Breadth)^2}

 \sf \mapsto {(Breadth)^2\ =\ (1681\ -\ 1600)cm^2}

 \sf \mapsto {(Breadth)^2\ =\ 81cm^2}

 \sf \mapsto {Breadth\ =\ \sqrt{81cm^2}}

 {\therefore{\underline{\boxed{\tt {Breadth\ of\ the\ rectangle\ =\ 9cm.}}}}}

  • Now we have the breadth of the rectangle.
  • So, by using the required formula we will find out the perimeter of the rectangle.

Required formula is as follows :-

 {\underline{\boxed{\sf {Perimeter\ of\ rectangle\ =\ 2(Length\ +\ Breadth)}}}}

Here,

  • Length = 40cm.
  • Breadth = 9cm.

By applying the values, we get :-

 \sf \mapsto {Perimeter\ of\ rectangle\ =\ 2(Length\ +\ Breadth)}

 \sf \mapsto {Perimeter\ of\ rectangle\ =\ 2(40cm\ +\ 9cm)}

 \sf \mapsto {Perimeter\ of\ rectangle\ =\ 2(49cm)}

 \sf \mapsto {Perimeter\ of\ rectangle\ =\ 2 \times 49cm}

 {\therefore{\underline{\boxed{\tt {Perimeter\ of\ rectangle\ =\ 98cm.}}}}}

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