find the perimeter of regular rectangle whose length three times of breadth if area is 900 square centimetre
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Explanation:
Area of rectangle=900cm^2
A.T.Q
Let breadth be x cm
So length=3x
3x*x=900
3x^2=900
x^2=300
x=√300
x=10√3cm
length=30√3cm
perimeter=2(l+b)
=2(10√3+30√3)
=2(40√3)
=80√3cm
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