Question

find the perimeter of rhombus find the perimeter of rhombus the length of whose diagonals are 16 and 13 cm

Answer 1

G I V E N :

• The length of diagonals of rhombus are 16 and 13 cm.

T O F I N D :

• The Perimeter of rhombus = ?

S O L U T I O N :

Given the length of two diagonals of rhombus, Let the two diagonals be x and y. Perimeter of the rhombus is given by :

• Perimeter of rhombus = 2√x² + y²

The values of the diagonals provided by the question are x = 16 cm, y = 13 cm, thus the perimeter is:

→ Perimeter of rhombus = 2√16² + 13²

→ Perimeter of rhombus = 2√256 + 169

→ Perimeter of rhombus = 2√425

→ Perimeter of rhombus = 2 × 20.6

→ Perimeter of rhombus = 41.2 cm

Therefore,the perimeter of rhombus is 41.2 cm.

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━

Extra Shots :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

═════════════════════════

Answer 2

Solution

Given ,

• a rhombus is having diagonals 16cm and 13cm .

To find ,

• we have to find the perimeter of the Rhombus .

We know that ,

• to find the perimeter of a rhombus we have to use the formula

=> perimeter of rhombus = 2√x^2 + y^2

So , here let X=16cm and y=13cm .

• putting the values in the formula we get an equation ; 2√16^2+13^2

solving this we get ;

=> 2√16^2+13^2

=> 2√256 +169

=> 2√425

=>2×20•6

=> 41.2 cm

The perimeter of the Rhombus is 41.2 CM .