Question

find the perimeter of rhombus if a diagnols are 25 and 42

Answer 1

$Heya !! \\ This \: is \: your \: answer. \\ Given \\ Diagonal1 = 25 units. \\ Diagonal2= 42 units.$
$Area \: of \: rhombus \: = \\ 1/2 \times d1 \times d2 \\ So, \\ Area = \frac{1}{2} \times 25 \times 42 \\ = 21 \times 25 \\ = 525 \: {units}^{2}$
$Also, \: area \: of \: rhombus \: \\ = {Side}^{2} \\ So, side = \sqrt{area} \\ = \sqrt{525} = \sqrt{3 \times 5 \times 5 \times7 } \\ = 5 \sqrt{21} \: units$
$Perimeter \: of \: rhombus \: = \: 4 \times side$

$So, \\ perimeter \: = 4 \times 5 \sqrt{21} \\ = 20 \sqrt{21} \: cm$
$Hence \: the \: perimeter \: of \: the \: \\ rhombus \: is \: 20 \sqrt{21} \: units.$
$Hope \: it \: helps$