Question

find the perimeter of rhombus if lengths of its diagonals are 10 cm and 24 cm ​

Answer 1

Answer:

Perimeter = 52cm

Step-by-step explanation:

$p = 4a$

$a = \sqrt{ \frac{p {}^{2} + q {}^{2} }{2} }$

$solving \: for \: p$

$p = 2 \sqrt{p {}^{2} +q {}^{2} }$

$2. \sqrt{10 {}^{2} + 24 {}^{2} }$

$52cm$

HOPE IT HELPS YOU .