find the perimeter of shaded region where adc aeb and bfc are semicircles on diameter ac ab and bc respectively
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[FIGURE IS IN THE ATTACHMENT]
Given:
Diameter of semicircle AEB= 2.8 cm
RADIUS OF SEMICIRCLE(AEB)= 2.8/2= 1.4 cm
Diameter of semicircle BFC=1.4 cm
RADIUS OF SEMICIRCLE(BFC)= 1.4/2= 0.7 cm
Diameter of semicircle ADC= 2.8+1.4 = 4.2 cm
RADIUS OF SEMICIRCLE(ADC) = 4.2/2= 2.1 cm.
Perimeter of the shaded region= sum of the arc of semicircle AEB, BFC and ADC= [π×1.4) +(π×0.7)+(π×2.1)] cm
= π(1.4+0.7+2.1) cm
=( 22/7) ×4.2
= 22× .6
= 13.2 cm
Hence, the perimeter of the shaded region is 13.2 cm
HOPE THIS WILL HELP YOU...
Given:
Diameter of semicircle AEB= 2.8 cm
RADIUS OF SEMICIRCLE(AEB)= 2.8/2= 1.4 cm
Diameter of semicircle BFC=1.4 cm
RADIUS OF SEMICIRCLE(BFC)= 1.4/2= 0.7 cm
Diameter of semicircle ADC= 2.8+1.4 = 4.2 cm
RADIUS OF SEMICIRCLE(ADC) = 4.2/2= 2.1 cm.
Perimeter of the shaded region= sum of the arc of semicircle AEB, BFC and ADC= [π×1.4) +(π×0.7)+(π×2.1)] cm
= π(1.4+0.7+2.1) cm
=( 22/7) ×4.2
= 22× .6
= 13.2 cm
Hence, the perimeter of the shaded region is 13.2 cm
HOPE THIS WILL HELP YOU...
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Answer:- Perimeter of the shaded region is 13. 2 cm.
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