Find the perimeter of square whose area is 39.69
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let, the arm of the square is a
then, area= 39.69 unit^2
or, a^2=39.69
or, a=√(39.69) = 6.3 unit.
so, the perimeter is P= 4a
or, perimeter P=4×6.3=25.2 unit.
then, area= 39.69 unit^2
or, a^2=39.69
or, a=√(39.69) = 6.3 unit.
so, the perimeter is P= 4a
or, perimeter P=4×6.3=25.2 unit.
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