Question

Find the perimeter of square whose diagonal is 10√2 cm( please solve it step by step)​

Answer 1

Given:

Diagonal of a square measures 10√2 cm

To Find:

Perimeter of the square

Solution:

Let each side of the square measure be s

A right triangle is formed including the diagonal, refer to the attached diagram.

According to Pythagoras theorem,

    H² = B² + P²

⇒  (10√2)² = s² + s²

⇒ (10x10x√2x√2) = 2s²

⇒ 200 = 2s²

∴ s² = (200/2) = 100

⇒ s = √100 = 10

So, each side of the square is 10cm

Perimeter of square = 4 x side

⇒ P = (4 x 10) = 40 cm

Hence, the perimeter of given square is 40cm

Answer 2

Answer:

40 Units

Step-by-step explanation:

Diagonal of square =$10\sqrt{2}$

​Side of square =​$\frac{10\sqrt{2} }{\sqrt{2\\} }$=10

Area of square =10×10=100 sq. units

The perimeter of square =4×10=40 units.