find the perimeter of square whose diagonal is 8 cm
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Answer:
16 under root 2
Step-by-step explanation:
Abcd is a square
Ac is diagonal =8 cm
By pythagoras theoram,
(AC) ^=(AB)^ + (BC)^
8^=s^+s^
64=2s^
64/2=s^
32=s^
S=4 under root 2
Perimeter of square = 4*side
so, 4*4 under root 2
= 16 under root 2...
Hope it helped uh
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