Find the perimeter of square whose side is 5x^2y^2+10xy+20
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Side= 5x^2y^2+10xy+20
Perimeter of square = 4×side
= 4×[5x^2y^2+10xy+20]
=20x^28y^2+40xy+80(Ans.)
Perimeter of square = 4×side
= 4×[5x^2y^2+10xy+20]
=20x^28y^2+40xy+80(Ans.)
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