Question

) Find the perimeter of square whose side
is 5x2 +1xy +20​

Answer 1

$Given \: side \: of \: square \: (a) = 5x^{2}+1xy+20$

$Perimeter \: of \:the \: square (P) = 4a$

$= 4(5x^{2}+1xy+20)$

$= 20x^{2}+4xy+80$

Therefore.,

$\red{Perimeter \: of \:the \: square }$

$\green {= 20x^{2}+4xy+80 }$

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