Question

Find the perimeter of the adjoining figure.

Answer 1

Answer:

$perimeter \: of \: the \: circle \: = 2\pi \: r \\ diameter = 21 \\ radius = \frac{21}{2} \\ \\ = 2 \times \frac{22}{7 } \ \times \frac{21}{2} \\ \\ \\ = \frac{22}{7} \times 21 \\ \\ = \frac{462}{7} \\ \\ = 66$

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Answer 2

GivEn:

• Diameter of semicircle = 21cm

To finD:

• Perimeter of semicircle

Solution:

Here, given that diameter of semicircle is 21 cm. To find it perimeter, we are using a formula :

Formula using:

Perimeter of semicircle = πr + 2r

Where,

• π = 22/7
• r = diameter/2 = 21/2 = 10.5cm

Putting values in formula :

Perimeter of semicircle = πr +2r

=> Perimeter of semicircle = $\large{\tt{\frac{22}{7}×10.5 + 2× 10.5}}$

=> Perimeter of semicircle = $\large{\tt{\frac{231}{7}+21}}$

=> $\large{\tt{\frac{231+147}{7}}}$

=> 378/7

=> 54cm

Therefore,

Perimeter of semicircle = 54cm.