find the perimeter of the figure obtained by joining the midpoints of the sides of a rectangle of length 24cm and 10cm, respectively
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Answered by
6
length of rectangle = 24cm
width = 10cm
by Pythagoras,
side of the figure obtained by joining the mid points of the rectangle
= √[ (12)^2 + (5)^2 ]
= √169 = 13cm
the obtained figure will be a square.
side = 13cm
then
perimeter of the obtained figure
= 4 × side = 4 × 13 = 52cm
Answer: perimeter = 52cm
width = 10cm
by Pythagoras,
side of the figure obtained by joining the mid points of the rectangle
= √[ (12)^2 + (5)^2 ]
= √169 = 13cm
the obtained figure will be a square.
side = 13cm
then
perimeter of the obtained figure
= 4 × side = 4 × 13 = 52cm
Answer: perimeter = 52cm
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siddharthbrainly2418:
right ans
see the attachment for diagram
Answered by
6
Perimeter of rectangle= 2(l+b)
=2(24+10)
=2(34)
=68cm2
So, perimeter of rectangle is 68.
Please, mark me brainlist.
=2(24+10)
=2(34)
=68cm2
So, perimeter of rectangle is 68.
Please, mark me brainlist.
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