Question

Find the perimeter of the following

Answer 1

Answer:

BD=√13²-12²=√169-144=√25=5cm

AD=AB-BD=14-5=9cm

AC=√12²+9²=√144+81=√225=15cm

Perimeter of triangle=x+y+z

=13+14+15=42cm

Hope you find it helpful.

Answer 2

Answer:

42cm

Step-by-step explanation:

Find DB using pythagoras theorum

$DB^{2}$= $13^{2}$-$12^{2}$

      = 169-144

      = 25 (25=$5^{2}$)

DB= 5cm

AB= 14cm given, AD= AB-DB= 14-5= 9cm

AC^2= 12^2 + 9^2

    = 144+81

    =225

AC=15cm

Perimeter = 14cm + 15cm +13cm = 42cm