find the perimeter of the following AB=2b+a BC=4b-3a AC=2a-3b
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perimeter of triangle
AB + BC + AC
= (2b + a) + (4b - 3a) + (2a - 3b)
= 2b + 4b - 3b + a - 3a + 2a
= 6b - 3b + 3a - 3a
= 3b
perimeter of triangle is 3b
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Answer: perimeter of triangle
AB + BC + AC
= (2b + a) + (4b - 3a) + (2a - 3b)
= 2b + 4b - 3b + a - 3a + 2a
= 6b - 3b + 3a - 3a
= 3b
Therefore, perimeter of a triangle =3b
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