Question

find the perimeter of the following figure​

Answer 1

Question:

• In triangle ABC, with sides $5\frac{2}{3},\: 4\frac{1}{3} \:and 5\frac{1}{4}$.Find its perimeter

Answer:

Perimeter of triangle = Sum of all sides

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=5\frac{2}{3}+4\frac{1}{3}+5\frac{1}{4}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{17}{3}+\frac{13}{3}+\frac{21}{4}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{68+52+63}{12}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{183}{12}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=15\frac{3}{12}$

$15\frac{1}{4}$

Hence, the perimeter of triangle ABC is $15\frac{1}{4}cm$

Extra Information:

• Perimeter: The perimeter of a plane figure is the length of its boundary.
• Area: The measurement of the region enclosed by a plane figure is called its area.

• Perimeter of square = (side×4)units

• Area of square = (side²) sq. units

• Perimeter of rectangle = 2(l + b) units

• Area of rectangle = (l × b) sq. units

• Perimeter of triangle = Sum of all sides $\rightarrow \boxed{This \:is \:used \:here.}$

• Area of triangle = $\frac{1}{2}\Big(base \times height\Big) sq.\:units$

• Circumference of circle = (2πr)units

• Area of circle = (πr²) sq. units