Find the perimeter of the following figure AB=8 cm 8 BC=3cm CD=5cm DE=6cm
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Step-by-step explanation:
Area of the quadrilateral = area of the triangle ABD + area of the triangle DBC.
From Abcd BC power 2 =DC power 2-bd power2
[Using Pythagoras theorem]
⟹BC =13 2−12 2=25
BC= 25 =5 cm
Area of the ΔDBC=1/2xbxH
=
1/2×5×12
=30 CM 2
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