Question

find the perimeter of the following parks park a 16 m length 30 m breadth and park b 16 m length 25 breadth find the perimeter both the park are chubbed together

Answer 1

perimeter of a rectangle is
2(L+B)
length is L
breadth is B
a) 2(16+30)
=> 2(46)
= 92m is the perimeter
b) 2(16+25)
=> 2(41)
= 82m is the perimeter.
when they are chubbed together.
the perimeter would be
2(16+30)
2(46)
92 is the perimeter.
when they are chubbed together.
the length (16) would overlap.
then breadth of the second rectangle.
which is (25) would go inside the breadth of the first rectangle which is (30) as perimeter is the outer part.
we have to consider it 30.
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Answer 2

perimeter of park A =2(16+30)=2×46=92m
perimeter of park B =2{16+25}=2×41=82m
if the parks are chubbed together then perimeter will be 2{16+55}=71×2=142 m


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