Find the perimeter of the following rectangles:
a) Length = 5cm, Breadth = 3cm
b) Length and Breadth are in the ratio 4:3 and area is 1200 sq. meters.
Answers
Answered by
5
a)
P = 2(l+b)
P = 2(8)
P = 16 cm
b) let length be 4x & breadth be 3x
ATQ.
A = 12x²
1200 = 12x²
x = 10 m
so , l = 40m
b = 30 m
so , P = 2× 70 = 140m
P = 2(l+b)
P = 2(8)
P = 16 cm
b) let length be 4x & breadth be 3x
ATQ.
A = 12x²
1200 = 12x²
x = 10 m
so , l = 40m
b = 30 m
so , P = 2× 70 = 140m
Answered by
1
a). Perimeter of a rectangle-= 2(l+b).
=2(5+3)
=16 cm.
b). Perimeter of a rectangle=2(l+b)
Area =1200
l*b=1200
But, l/b=4/3.
4x*3x=1200.
Therefore, l=40 m.
b=30 m.
Perimeter=2(40+30)
=2(70)
=140 m.
Hope this will help you.
=2(5+3)
=16 cm.
b). Perimeter of a rectangle=2(l+b)
Area =1200
l*b=1200
But, l/b=4/3.
4x*3x=1200.
Therefore, l=40 m.
b=30 m.
Perimeter=2(40+30)
=2(70)
=140 m.
Hope this will help you.
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