Question

find the perimeter of the following rhombus ​

Answer 1

Answer:

52 cm

Explanation:

Let the side AD be x.

Using Pythagoras Theorem,

$(12)^2+(5)^2 = x^2\\=> 144 + 25 = x^2\\=> 169 = x^2\\=> x = \sqrt{169} \\=> x = 13$

Hence, side of rhombus = 13 cm

Perimeter = 4 x 13 cm = 52 cm  

Answer 2

Answer:

perimeter is 52 cm

Step-by-step explanation:

since diagonals bisect each other,od=ob

ob=5cm,oa=12cm

by py thrm,

ab^2=ob^2+oa^2

ab^2=5^2+12^2

ab=13 cm

perimeter = 13*4=52cm

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