find the perimeter of the following shapes to 1 d.p take pi 3.14
Answers
Answer:
(i) Given that,
Diameter of semicircle = 6 cm
Radius = 3 cm
Now,
Perimeter = πr
= 3.14 × 3
= 9.42 cm
(ii) ⇒ Perimeter of the Semi-Circle = 26.69 m
Perimeter of the Shape = 44 m + 26.69 m - One Common side
Perimeter of the Shape = 70.69 m - 17 m
Perimeter of the Shape = 53.69 m
(iii) Radius of both circles = 16 cm / 2
= 8 cm
Perimeter of the figure = Circumference of 2 semicircles + 2 Breadth of the rectangles
= 2 × 1 / 2 × 2 π r + 2 × 3 cm
= 2 π r + 6 cm
= 2 × 3.14 × 8 cm + 6 cm
= 50.24 cm + 6 cm
= 56.24 cm
(iv) Radius of big semi circle = 8 cm / 2
= 4 cm
Radius of small semi - circle = 4 cm / 2
= 2 cm
Perimeter = 4 cm + 3 cm + 3 cm + circumference of the small semicircle + circumference of big semi circle.
= 10 cm + 1/2 × 2 π r + 1/2 × 2 π r
= 10 cm + 3.14 × r + 3.14 × r
= 10 cm + 3.14 × 4 + 3.14 × 2
= 10 cm + 12.56 + 6.28
= 28.84
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Hope it helps you!!
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