find the perimeter of the given figure the measurements are in cm
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Answer:
here, TXY is a right angled triangle.
According to Pythagoras Theorem-
h²= b² + h²
(TY)² = 8²+15²
(TY)² = 64+ 225
(TY)² = 289
(TY) = √ 289
(TY)= 17
here, TWZ is a right angled triangle
According to Pythagoras theorem
h² = b²+h²
(TZ)² = 12²+5²
(TZ)² = 144+25
(TZ)²= 169
(TZ)=√169
(TZ)= 13
Perimeter of figure = sum of outer boundary
XT+ XY+ YZ+ ZW+ WT
15+8+4+12+5
= 44 cm.
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