Find the perimeter of the given triangle:
Please explain how!
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Step-by-step explanation:
Hypotenuse=4x+3 Sides=x, 3x+3
We know that in a right angled triangle
Hypotenuse ²=Side1²+Side2²
So, (4x-3)²=x²+(3x+3)²
16x²-24x+9=x²+9x²+9x+9
16x²-24x+9=10x²+9x+9
6x²-33x=0
3x(2x-11)=0
x=0 or x= 11/2
If x=0 then sides would be 3 3 and 0
There is no possibility of side length 0
So x=0 doesn't satisfy the condition
If x= 11/2
Hypotenuse= 4(11/2)-3= 22-3= 19
Side 1=3(11/2)+3=26.5+3=29.5
Side 2=x= 11/2= 6.5
Perimeter=19+29.5+6.5=19+36=55
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