Question

Find the perimeter of the minor segment formed by a chord AB subtending an

angle of 60⁰ at the centre of a circle of radius 7cm.​

Answer 1

Answer:

43/3 cm. or 14.33 cm.

Step-by-step explanation:

Let O be the center of a circle whose radius is 7 cm and a cord AB such that

angle AOB=60°. In triangle AOB. , OA=OB (radii of the same circle).

Therefore angle OAB=angle OBA = x°(let)

angle OAB+angle OBA+angle AOB=180°

x°+x°+60°=180°

or 2x=120°. => x =60°

Thus ,angles are 60°,60° and 60°.

Therefore. AB=AO=BO. Thus , AB=7 cm.

Perimeter of minor sector = AB+(60°/360°) of circumference of the circle.

= 7 cm + (1/6)×2×(22/7)×7 cm.

= 7 cm +22/3 cm

= 43/3 cm. or 14.33 cm.

Answer 2

Answer:

23.3 cm.

Step-by-step explanation:

Hope it will helps you