Find the perimeter of the of a rectang whose breadth is 6 cm and one diagonals is 10 cm
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Answered by
1
Answer:
perimeter of rectangle = 6cm+6cm+10cm+10cm
= 32cm
Answered by
10
formula for diagonal of a rectangle
= d= root(l ^2 + b^2)
= 10cm = root (l^2 + 36cm^2)
Squaring both sides,
=100cm^2 = l^2 + 36cm^2
= l^2 = 64cm^2
= l = 8cm
Perimeter
= 2(l+b)
= 2(8cm + 6cm)
= 2(14cm)
=28cm
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