Question

find the perimeter of the of the triangle AbCIf Ab :8cm bc :3cm cA :5cm​

Answer 1

Answer:

Area of the quadrilateral = area of the triangle ABD + area of the triangle DBC.

From ΔDBC, BC

2

=DC

2

−BD

2

[Using Pythagoras theorem]

⟹BC

2

=13

2

−12

2

=25

⟹BC=

25

=5 cm

Area of the ΔDBC=

2

1

×b×h

=

2

1

×5×12

=30 cm

2

Area of the ΔABD=

s(s−a)(s−b)(s−c)

Here, s=

2

10+12+8

=15 cm

∴ Area of the ΔABD=

15(15−10)(15−12)(15−8)

=15

7

cm

2

∴ area of the quadrilateral=15+15

7

=15(1+

7

) cm

2

Step-by-step explanation:

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