Question

Find the perimeter of the polygon defined by the coordinates (5, 12), (12, 0), (0, 0), and (-4, 12). (Round to nearest tenth)

Answer 1

Answer:

47.5 is the perimeter of the polygon rounded to the nearest tenth

Step-by-step explanation:

Answer 2

The perimeter of the polygon is 47.54 unit length.

•) let A(5,12) , B(12,0) , C(0,0) and D(-4,12) such that AB , BC , CD and AD are the sides of that polygon.

•) Now we know that distance between two points in two dimention is:-

d = [(Y1 - Y2)^2 + (X1-X2)^2 ]^½

Now in the polygon ABCD ,

•) AB = [(12 - 5)^2 + ( 12-0)^2]^½

AB = √193

AB = 13.89

•) BC = √ (12)^2

BC = 12

•) CD = [16 + 144]^½

CD = √160 = 12.65

•) AD = √(9)^2

AD = 9

•) Now perimeter of a polygon is sum of all sides ie

AB + BC + CD + AD

=> 13.89 + 12 + 12.65 + 9

=> 47.54