Math, asked by shubhrajena, 6 hours ago

find the perimeter of the rectangle​

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Answers

Answered by snehakarmakar753
0

Step-by-step explanation:

Area of 1st box = 25cm²

Area of 2nd box = 25 × 2 = 50cm²

Breadth = 7cm

Length = 2( l+b ) =50cm²

= 2( l+7 ) = 50 cm²

= l + 7 = 50/2=25cm

= l = 25-7 = 18cm

= Length is 18cm

Hope This Help You

Answered by rosey25
139

Answer:

Answer:-

☞Given:-

✏Diagonal of the rectangle (D)✒ 25 cm

✏Length of the rectangle (l)✒7 cm

Now we have to find the area perimeter of a rectangle

✏Consider the breadth of the rectangle✒ (b)

Using Pythagoras theorem in triangle ABC ,

(ac) {}^{2}  = (b) {}^{2}  + (bc) {}^{2}

AC= 25 cm

AB= ?

BC=7 cm

Now put the values

(25) {}^{2}  = (b) {}^{2}  + (7) {}^{2}

Substuting the values

625 = b {}^{2}  + 49

625 - 49 = b {}^{2}

576 = b {}^{2}

b =  \sqrt{576}  = 24

Now we get breadth of rectangle = 24 cm

Area of Rectangle = Length × breadth

= 24×7

=168 cm^2

Perimeter of Rectangle= 2(l+b)

= 2(7+24)

=2×31

= 62

Hence,

62 is perimeter of Rectangle

i hope it helps you

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