Question

find the perimeter of the rectangle​

Answer 1

Step-by-step explanation:

Area of 1st box = 25cm²

Area of 2nd box = 25 × 2 = 50cm²

Breadth = 7cm

Length = 2( l+b ) =50cm²

= 2( l+7 ) = 50 cm²

= l + 7 = 50/2=25cm

= l = 25-7 = 18cm

= Length is 18cm

Hope This Help You

Answer 2

Answer:

Answer:-

☞Given:-

✏Diagonal of the rectangle (D)✒ 25 cm

✏Length of the rectangle (l)✒7 cm

Now we have to find the area perimeter of a rectangle

✏Consider the breadth of the rectangle✒ (b)

Using Pythagoras theorem in triangle ABC ,

$(ac) {}^{2} = (b) {}^{2} + (bc) {}^{2}$

AC= 25 cm

AB= ?

BC=7 cm

Now put the values

$(25) {}^{2} = (b) {}^{2} + (7) {}^{2}$

Substuting the values

$625 = b {}^{2} + 49$

$625 - 49 = b {}^{2}$

$576 = b {}^{2}$

$b = \sqrt{576} = 24$

Now we get breadth of rectangle = 24 cm

Area of Rectangle = Length × breadth

= 24×7

=168 cm^2

Perimeter of Rectangle= 2(l+b)

= 2(7+24)

=2×31

= 62

Hence,

62 is perimeter of Rectangle

i hope it helps you