Question

find the perimeter of the rectangle field whose length is 4 times its width and which has a area equal to 20736 square metre

Answer 1

$x = \sqrt{5184 } \\ x = 72 \\ bredth = 7 \\ length = 7 \times 4 = 28 \\ perimeter \: of \: rectangle =2(l + b \\ 2( 28 + 7) \\ 2(35) \\ 7$