Question

find the perimeter of the rectangle if its area is 768 square metre and the length is 32

Answer 1

b=a/l
b=768/32
b=24 m

p=2(l+b)
p=2(32+24)
p=64+48
p=112m^2

Answer 2

perimeter of rectangle = 2(l+b)

l = length = 32 m

b = breadth


Area of rectangle =
$l \times b {m}^{2} \\ \\ 768 = b \times 32 \\ \\ b = \frac{768}{32} \\ \\ b = 24 \: m$

perimeter =
$2(l + b) \: m \\ \\ = 2(32 + 24) \\ \\ = 2 \times 56 \\ \\ = 112 \: m$
Perimeter is 112 m.