Question

find the perimeter of the rectangle in which length-9, breadth-7​

Answer 1

Answer:

2×(9+7)

=2×16

=32

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Answer 2

☆ Solution ☆

Given :-

• Length of the rectangle is 9 unit.

• Breadth of the rectangle is 7 unit.

To Find :-

• The perimeter of rectangle.

Step-by-Step-Explaination :-

As we know that :-

Perimeter of rectangle = 2 ( length + breadth )

Where,

• Length of the rectangle = 9 unit.

• Breadth of the rectangle = 7 unit.

Putting the respective value,

Perimeter of rectangle = 2 ( 9 + 7 )

Perimeter of rectangle = 2 × 16

Perimeter of rectangle = 32

Hence,

The perimeter of the rectangle is 32 unit.

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Know More :-

Perimeter of Rectangle = 2( L + B )

Perimeter of square = 4 × Side

Perimeter of triangle = AB + BC + CA

Area of Rectangle = L × B

Area of Square = ( side ) ²

Area of Rhombus = Product of Diagonal/2.

Area of Parallelogram = Base × Height.

Area of triangle = 1/2 × base × height .

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