find the perimeter of the rectangle whose breadth is 8cm and a diagonal is 17
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Answer:
The answer is 46 cm
Step-by-step explanation:
let the rectangle be ABCD
let its breadth be = BC = AD = 8 cm
let its diagonal be BD = 17 cm
Let the length be = AB = CD = x cm
Now, the triangle DAB is a right-angle triangle where ∠A is 90°
∴ By using the Pythagoras theorem,
AB² + AD² = BD²
x² + 8² = 17²
x² = 289 − 64
x² = 225
x = √ 225
x = 15 cm
Thus, the Perimeter = 2 × ( 15 + 8 )
= 2 × 23
= 46 cm
!!!! THEREFORE, THE CORRECT ANSWER IS 46 cm !!!!
!!!! THUS, FINALLY, YOU'VE GOT THE ANSWER !!!!
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