Question

Find the perimeter of the rectangle whose breadth is 8m and a diagonal is 17m.
fast plz plz

Answer 1

Answer:

17+8+17+8=50

answer - 50

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Answer 2

Answer:

rectangle ABCD has

Breadth =BC=AD=8 cm

Diagonal BD=17 cm

Let the length =AB=CD=x cm

Now, triangle DAB is a right-angle triangle.

So, from Pythagorus theorem,

AB²+ AD²= BD²

X² +8² = 17²

X² = 289-64

X² = 225

X = √225

X = 15cm