find the perimeter of the rectangle whose lenght is 8 cm and a diagonal is 10 cm
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Here,
L= 8cm
B=16cm
D=10cm
perimeter of the rectangle= 2(l+b)
= 2(8+b)
= 16+b
b= 16cm
perimeter of the rectangle= 2(l+b)
perimeter of the rectangle= 2(8+16)
perimeter of the rectangle= 2×24
perimeter of the rectangle= 48cm²
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