Math, asked by akshDeep109, 10 months ago

Find the perimeter of the rectangle whose length = 40cm and diagnol =41cm

Answers

Answered by danialkohandel
0

Answer:

98

Step-by-step explanation:

According to the Faitha theorem we have Ghorth:

41^2=40^2+y^2

1681=1600+y^2

81=y^2

y=9

rectangle circumference=(40+9)*2=98

Answered by MonirAkhtar
5

Step-by-step explanation:

go through this solution

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