find the perimeter of the rectangle whose length is 103/7cm and the breadth is 81/2 cm
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Step-by-step explanation:
perimeter of rectangle= 2(l+b)
= 2( 103/7+81/2)
= 2 × (1442+567/14)
= 2× 2009/14
= 4018/14
= 287
so the answer is 287
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