Find the perimeter of the rectangle whose length is 12cm and a diagonal is 15cm.
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Given :-
Length => 12 cm
Diagonal => 15 cm
To find :-
Perimeter of the rectangle
Solution :-
Using Pythagoras theorem, we have:
(H)² = (P)² + (B)²
(15)² = (12)² + (B)²
225 = 144 + (8)²
(B)² = 225 – 144
(B)² = 81
B = √81
B = 9
Now,
Perimeter of a rectangle => 2 × (Length + Breadth)
Perimeter of the rectangle => 2 × (12 + 9) cm
Perimeter of the rectangle => 2 × 21 cm
Perimeter of the rectangle => 42 cm
Hence, the perimeter of the rectangle is 42 cm.
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