Question

Find the perimeter of the rectangle whose length is 13/6 m and breadth is 5/6m​

Answer 1

Answer:

6m

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Step-by-step explanation:

l = 13/6m

b = 5/6m

perimeter = 2(l+b)

$= 2(\frac{13}{6} + \frac{5}{6})$m

$= 2(\frac{13+5}{6})$m

$= 2(\frac{18}{6})$m

$= 2(\frac{3}{1})$ m (simplification)

= 2 x 3m

= 6m

Answer 2

Answer:

Step-by-step explanation: AB = CD = 5 cm and BC = AD = 3 cm

So, the perimeter of the rectangle ABCD = AB + BC + CD + AD = 5 cm + 3 cm + 5 cm + 3 cm = 16 cm

It can be written as 5 cm + 5 cm + 3 cm + 3 cm

                       = (2 × 5) cm + (2 × 3) cm

                       = 2 (5 + 3) cm

                       = 2 × 8 cm

                       = 16 cm

We add length and breadth twice to find the perimeter of a rectangle.

Perimeter of a rectangle = 2 (length + breadth)