Find the perimeter of the rectangle whose length is 15 cm and a diagonal is 25 cm.
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Given
L=15 (Length = L;B = Breadth;H = diagonal)
H=17 cm
L^2 + B^2 = H^2
⇒(15)^2 + B^2 = (17)^2
⇒225 + B^2 = 289
⇒B^2 = 289−225
⇒B^2 = 64
⇒B= Square root of 64
⇒B=8 cm.
Breadth =8 cm.
Area of rectangle =L×B=15×8=120m^2
Perimeter of rectangle =2(L+B)
=2(15+8)
=2(23)
=46cm
In this answer ^2 means square or power two
L=15 (Length = L;B = Breadth;H = diagonal)
H=17 cm
L^2 + B^2 = H^2
⇒(15)^2 + B^2 = (17)^2
⇒225 + B^2 = 289
⇒B^2 = 289−225
⇒B^2 = 64
⇒B= Square root of 64
⇒B=8 cm.
Breadth =8 cm.
Area of rectangle =L×B=15×8=120m^2
Perimeter of rectangle =2(L+B)
=2(15+8)
=2(23)
=46cm
In this answer ^2 means square or power two
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