Question

Find the perimeter of the rectangle whose length is 15 cm and a diagonal is 17 cm.​

Answer 1

Answer:

l=length,b=breadth,h=height

h=17

l^2+b^2=h^2

15^2+b^2=17^2

b^2=289-225=64

b=8

perimeter of rectangle=2(l+b)

=2(15+8)

=2(23)

=46

Step-by-step explanation:

Answer 2

Answer:

The perimeter of the rectangle is 46 cm

Step-by-step explanation:

Given :

• The length of the rectangle is 15 cm
• The diagonal of the rectangle is 17 cm

To find :

the perimeter of the rectangle

Solution :

To find the perimeter, we must know the value of breadth of the rectangle.

In a rectangle, (By Pythagoras theorem)

diagonal² = breadth² + length²

17² = breadth² + 15²

289 = breadth² + 225

breadth² = 289 – 225

breadth² = 64

breadth = √64

breadth = 8 cm

Therefore, the breadth of the rectangle is 8 cm

Perimeter of the rectangle = 2(length + breadth)

= 2(15 + 8)

= 2(23)

= 46 cm

Hence, the perimeter of the rectangle is 46 cm