Question

Find the perimeter of the rectangle whose length is 15 cm and a diagonal
is 17 cm.
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Answer 1

Answer:

64 is the answer b 15

$15 \times 2 + 17 \times 2 = 64$

Answer 2

answer.

diagonal=17

length=15

by pythagoreus theorm

(diagonal)^2=(length)^2+(breath)^2

17^2=15^2+b^2

289=225+b^2

289-225=b^2

64=b^2

(8)^2=b^2

b=8

peri.of rectangle=2(l+b)

=2(15+8)

=2×23

=46