Question

find the perimeter of the rectangle whose length is 2 cm and diagonal is 2.5 CM

Answer 1

Diagonal² = l² + b²
2.5² = 2² + b²
6.25 = 4 + b²
6.25 - 4 = b²
2.25 = b²
b = √2.25
b = 1.5cm

Now,

Perimeter of the rectangle = 2 ( l + b )
= 2 ( 2 + 1.5 )
= 2 × 3.5
= 7cm

Answer 2

Answer:

7cm

Step-by-step explanation:

using Pythagoras theorem

diagonal square = lenght^2 + breadth^2

2.5^2 = 4 + b^2

6.25 - 4 = b^2

b^2 = 2.25

b=1.5

perimeter of a rectangle is 2(l + b)

length= 2cm

breadth= 1.5cm

Perimeter = 2( 2 + 1.5)

Perimeter = 2 X 3.5

Perimeter = 7cm

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