find the perimeter of the rectangle whose length is 24 cm and diagonal is 25 CM ans is 50
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Answer:
Step-by-step explanation:
It is given that,
Length = 24 cm.
Diagonal = 25 cm.
Consider the breadth of a rectangle = b m.
Using Pythagoras theorem in triangle ABC,
AC
2
=AB
2
+BC
2
Substituting the values,
252=242+b
2
625=576+b
2
By further calculation,
b
2
=625–576=49
b=
49
=7 cm.
Here the perimeter of rectangle = 2(l+b)
Substituting the values,
=2(24+7)
So we get,
=2(31)
=62 cm.
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