Question

find the perimeter of the rectangle whose length is 35 cm and a diagonal is 63 cm.​

Answer 1

Hope my answer helps you ✌️

Answer 2

$\huge\mathfrak{Solution}$

◆ Length of the rectangle = 35 cm

◆ Diagonal of the rectangle = 63 cm

[ Since, according to the pythagoras theorem, Hypotenuse² = base² + height² , and here as all the angles of rectangle are 90° , so the diagonals obviously will be the hypotenuse , the length as base and the breadth as height ]

$\sf\boxed{\:★\:Pythagoras\:theorem\: ➡ \:Diagonal²\:= \:Length²\:+\:Breadth²}$

Diagonal² = Length² + Breadth²

✍ Breadth² = 63² - 35²

✍ Breadth² = 3969 - 1225

✍ Breadth = √2744 = 52.38 cm

$\bf\boxed{Perimeter\:= \:2\:×(\: Length\: + \:Breadth\:)}$

Perimeter = 2 ( 63 + 52.38 )

☆ Perimeter = 2 × 115.38

☆ Perimeter = 230.77 cm

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Notes ⭐

◎ Refer to the attachment for the diagram of your rectangle

◎ Area of the rectangle = Length × Breadth

◎ The unit while doing area will become square ( ² ) such as cm² , m²

◎ All he sides of rectangle measure 90°