Question

find the perimeter of the rectangle whose length is 40 centimetre and d is diagonal 41 cm
please give me answer​

Answer 1

Answer:

98 cm

Step-by-step explanation:

since the length is 40 cm and diagonal is 41 cm,using Pythagoras theorem we get the breadth of the rectangle as 9

so the perimeter is 2(l+b) which is 2(40+9)

thus the perimeter of the rectangle is 98 cm

Answer 2

Answer:

Hope you can understand it easily....................

Step-by-step explanation:

We know that a diagonal of a rectangle divides it into two right angle triangle / -

Hence /- Applying pythagoras theorem. ....

Or, Digonal^2 = Length^2 + Breadth^2

Or, (41)^2 = (40)^2 + Breadth^2

Or, 41)^2 - (40)^2 = Breadth^2

Or, 1681 - 1600 = Breadth^2

Or, √(81) = √(Breadth^2)

Or, √(81) = Breadth

Or, Breath = 9 Cm

Now, Perimeter of the rectangle /-

= 2 ( Length + Breadth )

= 2 ( 40 Cm + 9 Cm )

= 2 (49 Cm )

= 98 Cm ( Answer )

Therefore , Perimeter of the rectangle will be 98 Cm.